譯碼器控制數(shù)碼管為什么這個(gè)程序，無(wú)法把ledbuff[]的值賦給P0？

ID:155598 · 發(fā)表于 2017-3-23 09:56

為什么這個(gè)程序，無(wú)法把ledbuff[]的值賦給P0？

#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
#define ulong unsigned long
uchar code table[]={
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71};
uchar ledbuff[8]={
0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00};
sbit SA=P1^0;
sbit SB=P1^1;
sbit SC=P1^2;
uint time=0;
ulong sec=0;
uchar i=0;
void main()
{       TMOD=0x01;
TH0=(65536-1000)/256;
TL0=(65536-1000)%256;
TR0=1;
      while(1)
      {
      if(TF0==1)
         {
                     TF0=0;
                     TH0=(65536-2000)/256;
         TL0=(65536-2000)%256;
                     time++;
                     if(time>=1000)
                        {
                                 time=0;
                              sec++;
                              ledbuff[0]=table[sec%10];
                              ledbuff[1]=table[sec/10%10];
                              ledbuff[2]=table[sec/100%10];
                              ledbuff[3]=table[sec/1000%10];
                              ledbuff[4]=table[sec/10000%10];
                              ledbuff[5]=table[sec/100000%10];
                              ledbuff[6]=table[sec/1000000%10];
                              ledbuff[7]=table[sec/10000000%10];
                        }
                     switch(i)
                              {case 0:SC=1;SB=1;SA=1;P0=ledbuff[0];break;
                              case 1:SC=1;SB=1;SA=0;P0=ledbuff[1];break;
                              case 2:SC=1;SB=0;SA=1;P0=ledbuff[2];break;
                              case 3:SC=1;SB=0;SA=0;P0=ledbuff[3];break;
                              case 4:SC=0;SB=1;SA=1;P0=ledbuff[4];break;
               case 5:SC=0;SB=1;SA=0;P0=ledbuff[5];break;
                              case 6:SC=0;SB=0;SA=1;P0=ledbuff[6];break;
                           case 7:SC=0;SB=0;SA=0;P0=ledbuff[7];break;
                           default :break;
                     }
            }

      }

}